What is the monotone y=-3/(x+1) ?

The monotone y=-3/(x+1) is Increasing:-infinity <x<-1,Increasing:-1<x<infinity

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monotone y=-3/(x+1)

monotone intervals

y = - \frac{3}{x + 1}

Increasing : - \infty < x < - 1, Increasing : - 1 < x < \infty

Solution steps

f^{'} (x) = \frac{3}{( x + 1 ) ^{2}}

Find intervals:

Increasing

: - \infty < x < - 1,

Increasing

: - 1 < x < \infty

Increasing : - \infty < x < - 1, Increasing : - 1 < x < \infty

lo g_{3} (x + 2) - 1

s^{3}

f (x) = x^{6} - 4 x

\frac{x + 1}{x + 2}

y = 3 x

What is the monotone y=-3/(x+1) ?
The monotone y=-3/(x+1) is Increasing:-infinity <x<-1,Increasing:-1<x<infinity