What is the domain of y= 1/(t^2)cos^2(t) ?

The domain of y= 1/(t^2)cos^2(t) is t 0

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domain of y= 1/(t^2)cos^2(t)

domain

y = \frac{1}{t ^{2}} cos^{2} (t)

t < 0 or t > 0

Interval Notation

(- \infty, 0) \cup (0, \infty)

Solution steps

Find undefined (singularity) points:

t = 0

The function domain

t < 0 or t > 0

f (x) = (x^{2} - 3)^{2} (x^{2} + 3)^{2} = 0

f (x) = (x + 7)^{2}

\frac{3 x + 27}{x ^{2} + 6 x}

(x - 11)^{2} - 4

8 x + 6

What is the domain of y= 1/(t^2)cos^2(t) ?
The domain of y= 1/(t^2)cos^2(t) is t<0\lor t>0