What is the asymptotes of f(x)=(3x+1)/(4x^2-1) ?

The asymptotes of f(x)=(3x+1)/(4x^2-1) is Vertical: x=-1/2 ,x= 1/2 ,Horizontal: y=0

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asymptotes of f(x)=(3x+1)/(4x^2-1)

asymptotes

f (x) = \frac{3 x + 1}{4 x ^{2} - 1}

Vertical : x = - \frac{1}{2}, x = \frac{1}{2}, Horizontal : y = 0

Solution steps

Vertical asymptotes of

\frac{3 x + 1}{4 x ^{2} - 1} : x = - \frac{1}{2}, x = \frac{1}{2}

Horizontal Asymptotes of

\frac{3 x + 1}{4 x ^{2} - 1} : y = 0

Slant Asymptotes of

\frac{3 x + 1}{4 x ^{2} - 1} :

None

Vertical : x = - \frac{1}{2}, x = \frac{1}{2}, Horizontal : y = 0

(- 4, - 3), (6, - 7)

f (x) = \frac{9}{x ^{2} - 16}

\frac{1}{( x - 3 ) ^{3}}

\frac{2}{x + 7}

f (x) = x^{3} - 4 x^{2} + 6 x + 60

What is the asymptotes of f(x)=(3x+1)/(4x^2-1) ?
The asymptotes of f(x)=(3x+1)/(4x^2-1) is Vertical: x=-1/2 ,x= 1/2 ,Horizontal: y=0