What is the domain of h(x)= 6/((x+5)(x-3)) ?

The domain of h(x)= 6/((x+5)(x-3)) is x 3

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domain of h(x)= 6/((x+5)(x-3))

domain

h (x) = \frac{6}{( x + 5 ) ( x - 3 )}

x < - 5 or - 5 < x < 3 or x > 3

Interval Notation

(- \infty, - 5) \cup (- 5, 3) \cup (3, \infty)

Solution steps

Find undefined (singularity) points:

x = - 5, x = 3

The function domain

x < - 5 or - 5 < x < 3 or x > 3

\frac{y - 10}{y ^{2} + 3}

2 x - 44

0

\frac{x - 2}{x ^{2} + x - 6}

f (x) = \frac{x + 5}{x - 1}

What is the domain of h(x)= 6/((x+5)(x-3)) ?
The domain of h(x)= 6/((x+5)(x-3)) is x<-5\lor-5<x<3\lor x>3