What is the extreme x^4-x^2 ?

The extreme x^4-x^2 is Minimum(-1/(sqrt(2)),-1/4),Maximum(0,0),Minimum(1/(sqrt(2)),-1/4)

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extreme x^4-x^2

extreme points

x^{4} - x^{2}

Minimum (- \frac{1}{2}, - \frac{1}{4}), Maximum (0, 0), Minimum (\frac{1}{2}, - \frac{1}{4})

Solution steps

f^{'} (x) = 4 x^{3} - 2 x

Find intervals:

Decreasing

: - \infty < x < - \frac{1}{2},

Increasing

: - \frac{1}{2} < x < 0,

Decreasing

: 0 < x < \frac{1}{2},

Increasing

: \frac{1}{2} < x < \infty

Plug

x = - \frac{1}{2}

into

x^{4} - x^{2} : - \frac{1}{4}

Minimum (- \frac{1}{2}, - \frac{1}{4})

Plug

x = 0

into

x^{4} - x^{2} : 0

Maximum (0, 0)

Plug

x = \frac{1}{2}

into

x^{4} - x^{2} : - \frac{1}{4}

Minimum (\frac{1}{2}, - \frac{1}{4})

Minimum (- \frac{1}{2}, - \frac{1}{4}), Maximum (0, 0), Minimum (\frac{1}{2}, - \frac{1}{4})

x^{2} - 4 x + 3

y = sec (θ) (θ - tan (θ))

f (x) = \frac{1}{x + 2} - 3

4 sin (\frac{2 π θ}{5})

f (x) = x^{3} - 5 x + 1

What is the extreme x^4-x^2 ?
The extreme x^4-x^2 is Minimum(-1/(sqrt(2)),-1/4),Maximum(0,0),Minimum(1/(sqrt(2)),-1/4)