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Popular >

inflection ln(x^2+1)

Solution

inflection points

ln (x^{2} + 1)

Solution

(- 1, ln (2)), (1, ln (2))

Solution steps

f^{''} (x) = \frac{2 ( - x ^{2} + 1 )}{( x ^{2} + 1 ) ^{2}}

Find intervals:

Concave Downward

: - \infty < x < - 1,

Concave Upward

: - 1 < x < 1,

Concave Downward

: 1 < x < \infty

Plug

x = - 1

into

ln (x^{2} + 1) : ln (2)

(- 1, ln (2))

Plug

x = 1

into

ln (x^{2} + 1) : ln (2)

(1, ln (2))

(- 1, ln (2)), (1, ln (2))

Popular Examples

domain of f(x)=sqrt(23-x)domain

f (x) = 23 - x

slope of-1.4735x+91.61 slope

- 1.4735 x + 91.61

inverse of y=x^{1/2}-2 inverse

y = x^{\frac{1}{2}} - 2

inverse of f(x)=2^{(x+1)}inverse

f (x) = 2^{(x + 1)}

monotone f(x)=x^2+4x monotone intervals

f (x) = x^{2} + 4 x

Frequently Asked Questions (FAQ)

What is the inflection ln(x^2+1) ?
The inflection ln(x^2+1) is (-1,ln(2)),(1,ln(2))