What is the inverse of f(x)=2x^2-8x ?

The inverse of f(x)=2x^2-8x is (8+sqrt(64+8x))/4 ,(8-sqrt(64+8x))/4

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inverse of f(x)=2x^2-8x

inverse

f (x) = 2 x^{2} - 8 x

\frac{8 + 64 + 8 x}{4}, \frac{8 - 64 + 8 x}{4}

Solution steps

y = 2 x^{2} - 8 x

Replace

x

with

y

x = 2 y^{2} - 8 y

Solve for

y, x = 2 y^{2} - 8 y

\frac{8 + 64 + 8 x}{4}, \frac{8 - 64 + 8 x}{4}

(1.5) (5.6)

5 x^{3} - 15 x

x e^{- 2 x}

f (x) = x^{3} - 8 x^{2} + 9 x + 18

f (x) = \frac{( 3 x )}{( x - 2 )}

What is the inverse of f(x)=2x^2-8x ?
The inverse of f(x)=2x^2-8x is (8+sqrt(64+8x))/4 ,(8-sqrt(64+8x))/4