What is the critical f(x)=8x^3+x^2+8x ?

The critical f(x)=8x^3+x^2+8x is None

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critical f(x)=8x^3+x^2+8x

critical points

f (x) = 8 x^{3} + x^{2} + 8 x

None

Solution steps

8 x^{3} + x^{2} + 8 x

Find where

f^{'} (x)

is equal to zero or undefined

None

f (x) = \frac{5}{( x - 3 ) ^{2}}

f (x) = \frac{1}{2} x + 1

\frac{( x ^{2} - 4 )}{x ^{3} + x ^{2} - 4 x - 4}

y = 8

f (x) = 5 x^{2}