What is the inverse of f(x)= 1/3 (x-4)^2-2 ?

The inverse of f(x)= 1/3 (x-4)^2-2 is sqrt(3x+6)+4,-sqrt(3x+6)+4

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inverse of f(x)= 1/3 (x-4)^2-2

inverse

f (x) = \frac{1}{3} (x - 4)^{2} - 2

3 x + 6 + 4, - 3 x + 6 + 4

Solution steps

y = \frac{1}{3} (x - 4)^{2} - 2

Replace

x

with

y

x = \frac{1}{3} (y - 4)^{2} - 2

Solve for

y, x = \frac{1}{3} (y - 4)^{2} - 2

3 x + 6 + 4, - 3 x + 6 + 4

2 (1.2)

f (x) = \frac{2 x}{x}

f (x) = 4 x + 1

3 x - 2 y = 6

What is the inverse of f(x)= 1/3 (x-4)^2-2 ?
The inverse of f(x)= 1/3 (x-4)^2-2 is sqrt(3x+6)+4,-sqrt(3x+6)+4