What is the extreme f(x)=-x^3-6x^2+3 ?

The extreme f(x)=-x^3-6x^2+3 is Minimum(-4,-29),Maximum(0,3)

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extreme f(x)=-x^3-6x^2+3

extreme points

f (x) = - x^{3} - 6 x^{2} + 3

Minimum (- 4, - 29), Maximum (0, 3)

Solution steps

f^{'} (x) = - 3 x^{2} - 12 x

Find intervals:

Decreasing

: - \infty < x < - 4,

Increasing

: - 4 < x < 0,

Decreasing

: 0 < x < \infty

Plug

x = - 4

into

- x^{3} - 6 x^{2} + 3 : - 29

Minimum (- 4, - 29)

Plug

x = 0

into

- x^{3} - 6 x^{2} + 3 : 3

Maximum (0, 3)

Minimum (- 4, - 29), Maximum (0, 3)

f (x) = \frac{5 x ^{2} - 3}{x + 2}

x + 15

f (x) = \frac{1}{x + 2}

f (x) = \frac{3 x ^{2}}{x ^{2} - 4}

What is the extreme f(x)=-x^3-6x^2+3 ?
The extreme f(x)=-x^3-6x^2+3 is Minimum(-4,-29),Maximum(0,3)