What is the inverse of f(x)=(x^2-4)/(8x^2) ?

The inverse of f(x)=(x^2-4)/(8x^2) is sqrt(-4/(8x-1)),-sqrt(-4/(8x-1))

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inverse of f(x)=(x^2-4)/(8x^2)

inverse

f (x) = \frac{x ^{2} - 4}{8 x ^{2}}

- \frac{4}{8 x - 1}, - - \frac{4}{8 x - 1}

Solution steps

y = \frac{x ^{2} - 4}{8 x ^{2}}

Replace

x

with

y

x = \frac{y ^{2} - 4}{8 y ^{2}}

Solve for

y, x = \frac{y ^{2} - 4}{8 y ^{2}}

- \frac{4}{8 x - 1}, - - \frac{4}{8 x - 1}

f (x) = - 4 x^{3}

f (x) = 5 - 7 x

5 x + 3 y = 15

y = 3^{x}

2 (3 - x) = 6 y + 1

What is the inverse of f(x)=(x^2-4)/(8x^2) ?
The inverse of f(x)=(x^2-4)/(8x^2) is sqrt(-4/(8x-1)),-sqrt(-4/(8x-1))