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Popular >

f(x)=x^2+x+2

Solution

f (x) = x^{2} + x + 2

Solution

Domain : - \infty < x < \infty

Range : f (x) \geq \frac{7}{4}

Y Intercepts : (0, 2)

Vertex : Minimum (- \frac{1}{2}, \frac{7}{4})

Inverse : \frac{- 1 + 4 x - 7}{2}, \frac{- 1 - 4 x - 7}{2}

+1

Interval Notation

Domain : (- \infty, \infty)

Range : [\frac{7}{4}, \infty)

Solution steps

Domain of

x^{2} + x + 2 : - \infty < x < \infty

Range of

x^{2} + x + 2 : f (x) \geq \frac{7}{4}

Axis interception points of

x^{2} + x + 2 :

Y Intercepts

: (0, 2)

Vertex of

x^{2} + x + 2 :

Minimum

(- \frac{1}{2}, \frac{7}{4})

Inverse of

x^{2} + x + 2 : \frac{- 1 + 4 x - 7}{2}, \frac{- 1 - 4 x - 7}{2}

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- 2 - 3 cos (\frac{π x}{2})

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5 - 4 x^{3}

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f (x) = (5 x - 3)^{3}

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f (x) = 6 - (\frac{2}{2 x - 1})

Frequently Asked Questions (FAQ)

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