What is the domain of f(x)= 2/(sqrt(x+1)) ?

The domain of f(x)= 2/(sqrt(x+1)) is x>-1

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domain of f(x)= 2/(sqrt(x+1))

domain

f (x) = \frac{2}{x + 1}

x > - 1

Interval Notation

(- 1, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 1

Find undefined (singularity) points:

x = - 1

Combine real regions and undefined points for final function domain

x > - 1

f (x) = \frac{1}{3 x ^{2} + 3 x - 18}

f (x) = - 2 + 3 x - 3 x^{2}

f (x) = \frac{5 x + 35}{7 x}

(2, - 2), (5, 0)

2^{- x} + 4

What is the domain of f(x)= 2/(sqrt(x+1)) ?
The domain of f(x)= 2/(sqrt(x+1)) is x>-1