What is the domain of f(x)=\sqrt[4]{x^2+5x-6} ?

The domain of f(x)=\sqrt[4]{x^2+5x-6} is x = 1

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domain of f(x)=\sqrt[4]{x^2+5x-6}

domain

x \leq - 6 or x \geq 1

Interval Notation

(- \infty, - 6] \cup [1, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 6 or x \geq 1

The function domain

x \leq - 6 or x \geq 1

f (x) = 8 (x - 3)

f (x) = x - 5

f (x) = \frac{1}{( x - 2 ) ^{2}}

f (x) = \frac{x ^{3} - 8}{x ^{2} - 3 x + 2}

ln (x) - ln (x - 1)

What is the domain of f(x)=\sqrt[4]{x^2+5x-6} ?
The domain of f(x)=\sqrt[4]{x^2+5x-6} is x<=-6\lor x>= 1