What is the domain of f(x)=(sqrt(x+32))/(x-6) ?

The domain of f(x)=(sqrt(x+32))/(x-6) is -32 6

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domain of f(x)=(sqrt(x+32))/(x-6)

domain

f (x) = \frac{x + 32}{x - 6}

- 32 \leq x < 6 or x > 6

Interval Notation

[- 32, 6) \cup (6, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 32

Find undefined (singularity) points:

x = 6

Combine real regions and undefined points for final function domain

- 32 \leq x < 6 or x > 6

f (x) = \frac{3 x}{x - 2}

(0, - 3), (- 1, 15)

f (x) = \frac{( - 9 - 8 x )}{x - 1}

- x + 3

f (x) = \frac{x ^{2}}{( x - 2 ) ^{3}}

What is the domain of f(x)=(sqrt(x+32))/(x-6) ?
The domain of f(x)=(sqrt(x+32))/(x-6) is -32<= x<6\lor x>6