What is the domain of f(x)=ln(x^2+1) ?

The domain of f(x)=ln(x^2+1) is -infinity <x<infinity

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domain of f(x)=ln(x^2+1)

domain

f (x) = ln (x^{2} + 1)

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

Find positive values for logs:

- \infty < x < \infty

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

f (x) = \frac{1}{x - 5} + 4

- x + 3

f (x) = \frac{6 x}{x - 3}

(2, - 1), (4, 5)

f (x) = \frac{( x - 1 ) ^{2}}{x ^{2} + 2}

What is the domain of f(x)=ln(x^2+1) ?
The domain of f(x)=ln(x^2+1) is -infinity <x<infinity