What is the domain of f(x)=(sqrt(6+x))/(1-x) ?

The domain of f(x)=(sqrt(6+x))/(1-x) is -6 1

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domain of f(x)=(sqrt(6+x))/(1-x)

domain

f (x) = \frac{6 + x}{1 - x}

- 6 \leq x < 1 or x > 1

Interval Notation

[- 6, 1) \cup (1, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 6

Find undefined (singularity) points:

x = 1

Combine real regions and undefined points for final function domain

- 6 \leq x < 1 or x > 1

y = 3 x - x^{2} + 4

f (x) = - x^{3} - 3 x^{2}

f (x) = 2 x^{3} + 6

f (x) = 2 x^{3} - 3

f (x) = x^{3} - 3 x^{2} - x + 3

What is the domain of f(x)=(sqrt(6+x))/(1-x) ?
The domain of f(x)=(sqrt(6+x))/(1-x) is -6<= x<1\lor x>1