en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

midpoint (0,0),(2b,0)

Solution

midpoint

(0, 0), (2 b, 0)

Solution

(b, 0)

Solution steps

Midpoint of

(x_{1}, y_{1}), (x_{2}, y_{2})

:

(\frac{x _{2} + x _{1}}{2}, \frac{y _{2} + y _{1}}{2})

(x_{1}, y_{1}) = (0, 0), (x_{2}, y_{2}) = (2 b, 0)

= (\frac{2 b + 0}{2}, \frac{0 + 0}{2})

Refine

= (b, 0)

Popular Examples

range of-7/(2x^{3/2)}range

- \frac{7}{2 x ^{\frac{3}{2}}}

domain of f(x)=15x+12 domain

f (x) = 15 x + 12

extreme f(x)=(2-3x)/(e^x)extreme points

f (x) = \frac{2 - 3 x}{e ^{x}}

domain of f(x)=-4x+7 domain

f (x) = - 4 x + 7

f(x)=e^x+2e^{2x}

f (x) = e^{x} + 2 e^{2 x}

Frequently Asked Questions (FAQ)

What is the midpoint (0,0),(2b,0) ?
The midpoint (0,0),(2b,0) is (b,0)