What is the inverse of f(x)=(x^2-3)/2 ?

The inverse of f(x)=(x^2-3)/2 is sqrt(2x+3),-sqrt(2x+3)

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inverse of f(x)=(x^2-3)/2

inverse

f (x) = \frac{x ^{2} - 3}{2}

2 x + 3, - 2 x + 3

Solution steps

y = \frac{x ^{2} - 3}{2}

Replace

x

with

y

x = \frac{y ^{2} - 3}{2}

Solve for

y, x = \frac{y ^{2} - 3}{2}

2 x + 3, - 2 x + 3

f (x) = 4 (x + 1)^{2} - 3

x^{2} + 12 x + 36

y = 2 x^{2} - 8

\frac{x ^{3} - 9 x}{10}

f (x) = ln (\frac{x - 3}{x + 2})

What is the inverse of f(x)=(x^2-3)/2 ?
The inverse of f(x)=(x^2-3)/2 is sqrt(2x+3),-sqrt(2x+3)