What is the inverse of f(x)=(8+x)/(3x-2) ?

The inverse of f(x)=(8+x)/(3x-2) is (8+2x)/(3x-1)

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inverse of f(x)=(8+x)/(3x-2)

inverse

f (x) = \frac{8 + x}{3 x - 2}

\frac{8 + 2 x}{3 x - 1}

Solution steps

y = \frac{8 + x}{3 x - 2}

Replace

x

with

y

x = \frac{8 + y}{3 y - 2}

Solve for

y, x = \frac{8 + y}{3 y - 2}

\frac{8 + 2 x}{3 x - 1}

f (x) = \frac{1}{3} x^{3} - x^{2} - 8 x

f (x) = \frac{9}{5} + 32

f (x) = \frac{1}{x ^{2} + 6 x - 7}

f (x) = x^{4} - 4 x^{3} + 3 x + 5

f (x) = \frac{8 x - 3}{x}

What is the inverse of f(x)=(8+x)/(3x-2) ?
The inverse of f(x)=(8+x)/(3x-2) is (8+2x)/(3x-1)