What is the domain of f(x)= 1/(x^2+6x-7) ?

The domain of f(x)= 1/(x^2+6x-7) is x 1

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domain of f(x)= 1/(x^2+6x-7)

domain

f (x) = \frac{1}{x ^{2} + 6 x - 7}

x < - 7 or - 7 < x < 1 or x > 1

Interval Notation

(- \infty, - 7) \cup (- 7, 1) \cup (1, \infty)

Solution steps

Find undefined (singularity) points:

x = 1, x = - 7

The function domain

x < - 7 or - 7 < x < 1 or x > 1

f (x) = x^{4} - 4 x^{3} + 3 x + 5

f (x) = \frac{8 x - 3}{x}

y - 6 = (x + 2)^{2}

(0, 0), (3, 2)

(8, 0), (0, - 3)

What is the domain of f(x)= 1/(x^2+6x-7) ?
The domain of f(x)= 1/(x^2+6x-7) is x<-7\lor-7<x<1\lor x>1