What is the domain of f(x)= x/(x^2+13x+40) ?

The domain of f(x)= x/(x^2+13x+40) is x -5

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domain of f(x)= x/(x^2+13x+40)

domain

f (x) = \frac{x}{x ^{2} + 13 x + 40}

x < - 8 or - 8 < x < - 5 or x > - 5

Interval Notation

(- \infty, - 8) \cup (- 8, - 5) \cup (- 5, \infty)

Solution steps

Find undefined (singularity) points:

x = - 5, x = - 8

The function domain

x < - 8 or - 8 < x < - 5 or x > - 5

\frac{1}{x ^{2} - 4}

f (x) = (x - 8)^{\frac{1}{2}}

\frac{6 x - 5}{x + 9}

(- 5, 5), (2, 2)

ln (ln (ln (4 x)))

What is the domain of f(x)= x/(x^2+13x+40) ?
The domain of f(x)= x/(x^2+13x+40) is x<-8\lor-8<x<-5\lor x>-5