What is the domain of f(x)=sqrt(t^2+4) ?

The domain of f(x)=sqrt(t^2+4) is -infinity <t<infinity

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domain of f(x)=sqrt(t^2+4)

domain

f (x) = t^{2} + 4

- \infty < t < \infty

Solution steps

Find non-negative values for radicals:

- \infty < t < \infty

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < t < \infty

y = 2 x^{3} - 3 x^{2} - 9

- (x - 4)^{2} + 1

f (x) = 1. 5^{x} + 4

(- 2, - 1), (- 5, 8)

f (x) = \frac{5 x}{6 x + 7}

What is the domain of f(x)=sqrt(t^2+4) ?
The domain of f(x)=sqrt(t^2+4) is -infinity <t<infinity