What is the domain of f(x)=(sqrt(2x-4))/(x^2-9) ?

The domain of f(x)=(sqrt(2x-4))/(x^2-9) is 2 3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)=(sqrt(2x-4))/(x^2-9)

domain

f (x) = \frac{2 x - 4}{x ^{2} - 9}

2 \leq x < 3 or x > 3

Interval Notation

[2, 3) \cup (3, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 2

Find undefined (singularity) points:

x = 3, x = - 3

Combine real regions and undefined points for final function domain

2 \leq x < 3 or x > 3

f (x) = csc (x)

f (x) = 3 x^{5} - 30 x^{4}

f (x) = 6 x - 3

(8, 20), (2, 2)

f (x) = 19 cos (2 x) + 4

What is the domain of f(x)=(sqrt(2x-4))/(x^2-9) ?
The domain of f(x)=(sqrt(2x-4))/(x^2-9) is 2<= x<3\lor x>3