What is the inverse of f(x)=\sqrt[3]{4-x}+2 ?

The inverse of f(x)=\sqrt[3]{4-x}+2 is -x^3+6x^2-12x+12

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inverse of f(x)=\sqrt[3]{4-x}+2

inverse

- x^{3} + 6 x^{2} - 12 x + 12

Solution steps

Replace

x

with

y

Solve for

- x^{3} + 6 x^{2} - 12 x + 12

f (x) = x^{2} - 25, x \geq 5

\frac{x ^{2}}{x ^{2} - 9}

\frac{6 x}{5 x - 6}

y = cos (2 x)

\frac{x + 7}{x ^{2} - 14 x + 49}

What is the inverse of f(x)=\sqrt[3]{4-x}+2 ?
The inverse of f(x)=\sqrt[3]{4-x}+2 is -x^3+6x^2-12x+12