What is the inverse of f(x)=(3-2x)/(3-4x) ?

The inverse of f(x)=(3-2x)/(3-4x) is (3-3x)/(2(1-2x))

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inverse of f(x)=(3-2x)/(3-4x)

inverse

f (x) = \frac{3 - 2 x}{3 - 4 x}

\frac{3 - 3 x}{2 ( 1 - 2 x )}

Solution steps

y = \frac{3 - 2 x}{3 - 4 x}

Replace

x

with

y

x = \frac{3 - 2 y}{3 - 4 y}

Solve for

y, x = \frac{3 - 2 y}{3 - 4 y}

\frac{3 - 3 x}{2 ( 1 - 2 x )}

(5, - 4), (3, 2)

y = 3 x - 6

y = \frac{- 10 x - 7}{- 4 x - 2}

f (x) = \frac{5}{x - 2}

y = lo g_{2 x + 3} (x^{2} + 3 x - 4)

What is the inverse of f(x)=(3-2x)/(3-4x) ?
The inverse of f(x)=(3-2x)/(3-4x) is (3-3x)/(2(1-2x))