What is the critical x^{2/3}(x-5) ?

The critical x^{2/3}(x-5) is x=0,x=2

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critical x^{2/3}(x-5)

critical points

x^{\frac{2}{3}} (x - 5)

x = 0, x = 2

Solution steps

x^{\frac{2}{3}} (x - 5)

Find where

f^{'} (x)

is equal to zero or undefined

x = 2, x = 0

Identify critical points not in

f (x)

domain

Domain of

x^{\frac{2}{3}} (x - 5) : - \infty < x < \infty

All critical points are in domain

x = 0, x = 2

(4.6) (- 3.3)

x^{2} + 8 x + 14

\frac{1}{X ^{2}}

f (x) = x + 4 - 2

5 x + 15