What is the answer to D(r)= 23/20 r+4/3 ?

The answer to D(r)= 23/20 r+4/3 is r=(80)/(3(20D-23));\quad D\ne 23/20

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D(r)= 23/20 r+4/3

D (r) = \frac{23}{20} r + \frac{4}{3}

r = \frac{80}{3 ( 20 D - 23 )}; D \neq = \frac{23}{20}

Solution steps

D (r) = \frac{23}{20} r + \frac{4}{3}

Expand

D (r) : Dr

Dr = \frac{23}{20} r + \frac{4}{3}

Move

\frac{23}{20} r

to the left side

Dr - \frac{23}{20} r = \frac{4}{3}

Multiply both sides by

20

20 Dr - 23 r = \frac{80}{3}

Factor

20 Dr - 23 r : r (20 D - 23)

r (20 D - 23) = \frac{80}{3}

Divide both sides by

20 D - 23; D \neq = \frac{23}{20}

r = \frac{80}{3 ( 20 D - 23 )}; D \neq = \frac{23}{20}

f (x) = x^{4} - x^{2} + 2

f (x) = 4 x

f (x) = \frac{x ^{2} + 15 x + 54}{x + 6}

f (x) = - x + 6

y = \frac{5 x + 20}{x ^{2} - 16}

What is the answer to D(r)= 23/20 r+4/3 ?
The answer to D(r)= 23/20 r+4/3 is r=(80)/(3(20D-23));\quad D\ne 23/20