What is the domain of f(x)=(x^2)/(3-sqrt(2x-1)) ?

The domain of f(x)=(x^2)/(3-sqrt(2x-1)) is 1/2 5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)=(x^2)/(3-sqrt(2x-1))

domain

f (x) = \frac{x ^{2}}{3 - 2 x - 1}

\frac{1}{2} \leq x < 5 or x > 5

Interval Notation

[\frac{1}{2}, 5) \cup (5, \infty)

Solution steps

Find non-negative values for radicals:

x \geq \frac{1}{2}

Find undefined (singularity) points:

x = 5

Combine real regions and undefined points for final function domain

\frac{1}{2} \leq x < 5 or x > 5

f (x) = 3 x^{2} + 6 x + 1

ln (1)

x^{2} - 5 x

f (x) = 9 x + 48

y = x^{4} - x^{2} + 6

What is the domain of f(x)=(x^2)/(3-sqrt(2x-1)) ?
The domain of f(x)=(x^2)/(3-sqrt(2x-1)) is 1/2 <= x<5\lor x>5