What is the distance (1/2 ,4),(3/2 ,-1) ?

The distance (1/2 ,4),(3/2 ,-1) is square root of 26

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distance (1/2 ,4),(3/2 ,-1)

distance

(\frac{1}{2}, 4), (\frac{3}{2}, - 1)

26

Solution steps

The distance between

(x_{1}, y_{1}), (x_{2}, y_{2})

is:

(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}

The distance between

(\frac{1}{2}, 4)

and

(\frac{3}{2}, - 1)

= (\frac{3}{2} - \frac{1}{2})^{2} + (- 1 - 4)^{2}

Simplify

= 26

f (x) = 4 x + 12

y = x^{2} + 2 x + 1

f (x) = \frac{( x + 2 )}{2 ( x ^{2} - 2 )}

f (x) = - \frac{4}{x} + 1

(3, 1), (5, 3)

What is the distance (1/2 ,4),(3/2 ,-1) ?
The distance (1/2 ,4),(3/2 ,-1) is square root of 26