What is the asymptotes of f(x)= 1/((x+4)^2)-5 ?

The asymptotes of f(x)= 1/((x+4)^2)-5 is Vertical: x=-4,Horizontal: y=-5

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asymptotes of f(x)= 1/((x+4)^2)-5

asymptotes

f (x) = \frac{1}{( x + 4 ) ^{2}} - 5

Vertical : x = - 4, Horizontal : y = - 5

Solution steps

Vertical asymptotes of

\frac{1}{( x + 4 ) ^{2}} - 5 : x = - 4

Horizontal Asymptotes of

\frac{1}{( x + 4 ) ^{2}} - 5 : y = - 5

Slant Asymptotes of

\frac{1}{( x + 4 ) ^{2}} - 5 :

None

Vertical : x = - 4, Horizontal : y = - 5

f (x) = - x^{2} - 2 x - 1

\frac{4 x + 3}{x ^{2} + 3 x}

f (x) = 7 x - 5 = 4 y - 6

f (x) = y + 2 = - (x + 1)

f (x) = 10 x + 20

What is the asymptotes of f(x)= 1/((x+4)^2)-5 ?
The asymptotes of f(x)= 1/((x+4)^2)-5 is Vertical: x=-4,Horizontal: y=-5