What is the range of-sin(x-pi/6) ?

The range of-sin(x-pi/6) is -1<= f(x)<= 1

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range of-sin(x-pi/6)

range

- sin (x - \frac{π}{6})

- 1 \leq f (x) \leq 1

Interval Notation

[- 1, 1]

Solution steps

The range of the basic

sin

function is

- 1 \leq sin (x - \frac{π}{6}) \leq 1

- 1 \leq sin (x - \frac{π}{6}) \leq 1

Multiply the edges of the range by:

- 1

- 1 \leq - sin (x - \frac{π}{6}) \leq 1

Therefore the range is

- 1 \leq f (x) \leq 1

12

\frac{x}{- 2 + 3 x}

y - (3) = (1) (x - (4))

\frac{2 x ^{2} - 2 x - 24}{x ^{2} - 4 x + 3}