What is the inverse of sqrt((x-6)/(x-3)) ?

The inverse of sqrt((x-6)/(x-3)) is (-6+3x^2)/(x^2-1)

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inverse of sqrt((x-6)/(x-3))

inverse

\frac{x - 6}{x - 3}

\frac{- 6 + 3 x ^{2}}{x ^{2} - 1}

Solution steps

y = \frac{x - 6}{x - 3}

Replace

x

with

y

x = \frac{y - 6}{y - 3}

Solve for

y, x = \frac{y - 6}{y - 3}

\frac{- 6 + 3 x ^{2}}{x ^{2} - 1}

\frac{4}{x ^{2} + x - 2}

3^{x} - 2

f (x) = 2 x^{3} + 3 x^{2} - 72 x

f (x) = x 64 - x^{2}

f (- 3) = e^{x - 3}

What is the inverse of sqrt((x-6)/(x-3)) ?
The inverse of sqrt((x-6)/(x-3)) is (-6+3x^2)/(x^2-1)