What is the domain of y=sqrt(1/(x^2-4)) ?

The domain of y=sqrt(1/(x^2-4)) is x 2

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domain of y=sqrt(1/(x^2-4))

domain

y = \frac{1}{x ^{2} - 4}

x < - 2 or x > 2

Interval Notation

(- \infty, - 2) \cup (2, \infty)

Solution steps

Find non-negative values for radicals:

x < - 2 or x > 2

Find undefined (singularity) points:

x = 2, x = - 2

Combine real regions and undefined points for final function domain

x < - 2 or x > 2

\frac{2 x - 5}{x ^{2} - 3 x - 28}

f (x) = 3 \cdot e^{2 x}

\frac{x - 4}{x - 2}

f (x) = - 4 x^{2} - 20 x + 1

f (x) = ln (3 - 4 x^{2})

What is the domain of y=sqrt(1/(x^2-4)) ?
The domain of y=sqrt(1/(x^2-4)) is x<-2\lor x>2