What is the domain of f(x)=((x+1)^2)/(sqrt(2x-1)) ?

The domain of f(x)=((x+1)^2)/(sqrt(2x-1)) is x> 1/2

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domain of f(x)=((x+1)^2)/(sqrt(2x-1))

domain

f (x) = \frac{( x + 1 ) ^{2}}{2 x - 1}

x > \frac{1}{2}

Interval Notation

(\frac{1}{2}, \infty)

Solution steps

Find non-negative values for radicals:

x \geq \frac{1}{2}

Find undefined (singularity) points:

x = \frac{1}{2}

Combine real regions and undefined points for final function domain

x > \frac{1}{2}

y = - 5 sin (π - 4 x) + 1

\frac{x + 4}{x - 5}

f (x) = x^{2} - 4 x - 3

2 x - 5

y = 4 x - 2

What is the domain of f(x)=((x+1)^2)/(sqrt(2x-1)) ?
The domain of f(x)=((x+1)^2)/(sqrt(2x-1)) is x> 1/2