What is the domain of f(x)= 1/(sqrt(z-1)) ?

The domain of f(x)= 1/(sqrt(z-1)) is z>1

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domain of f(x)= 1/(sqrt(z-1))

domain

f (x) = \frac{1}{z - 1}

z > 1

Interval Notation

(1, \infty)

Solution steps

Find non-negative values for radicals:

z \geq 1

Find undefined (singularity) points:

z = 1

Combine real regions and undefined points for final function domain

z > 1

f (x) = x^{2} + 5

\frac{x - 3}{x - 10}

3 x^{4} - 20 x^{3} + 24 x^{2}

f (x) = \frac{- 3 x - 9}{x ^{2} - x - 12}

y = (5)^{x}

What is the domain of f(x)= 1/(sqrt(z-1)) ?
The domain of f(x)= 1/(sqrt(z-1)) is z>1