What is the domain of f(x)= 1/(sqrt(x^2-4x)) ?

The domain of f(x)= 1/(sqrt(x^2-4x)) is x 4

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domain of f(x)= 1/(sqrt(x^2-4x))

domain

f (x) = \frac{1}{x ^{2} - 4 x}

x < 0 or x > 4

Interval Notation

(- \infty, 0) \cup (4, \infty)

Solution steps

Find non-negative values for radicals:

x \leq 0 or x \geq 4

Find undefined (singularity) points:

x = 4, x = 0

Combine real regions and undefined points for final function domain

x < 0 or x > 4

f (x) = x^{3} - 4

lo g_{3} (x - 1) + 2

(- 7, 1), (5, - 7)

f (x) = \frac{x}{x + 6}

f (x) = \frac{2}{( x - 3 )}

What is the domain of f(x)= 1/(sqrt(x^2-4x)) ?
The domain of f(x)= 1/(sqrt(x^2-4x)) is x<0\lor x>4