What is the domain of f(x)=sqrt(3x-12) ?

The domain of f(x)=sqrt(3x-12) is x>= 4

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domain of f(x)=sqrt(3x-12)

domain

f (x) = 3 x - 12

x \geq 4

Interval Notation

[4, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 4

The function domain

x \geq 4

f (x) = e^{x}

f (x) = 4 + 6 x

2 x^{2} - 5 x + 3

\frac{x}{2} + cos (x)

f (x) = 8 (x - 8)^{3}

What is the domain of f(x)=sqrt(3x-12) ?
The domain of f(x)=sqrt(3x-12) is x>= 4