What is the domain of y=(sqrt(x+8))/(x-7) ?

The domain of y=(sqrt(x+8))/(x-7) is -8 7

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of y=(sqrt(x+8))/(x-7)

domain

y = \frac{x + 8}{x - 7}

- 8 \leq x < 7 or x > 7

Interval Notation

[- 8, 7) \cup (7, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 8

Find undefined (singularity) points:

x = 7

Combine real regions and undefined points for final function domain

- 8 \leq x < 7 or x > 7

\frac{1}{7 x - 21}

f (x) = e^{- x^{2}}

x^{2} - 6 x

7 y = 9

f (x) = x + 6 + 2

What is the domain of y=(sqrt(x+8))/(x-7) ?
The domain of y=(sqrt(x+8))/(x-7) is -8<= x<7\lor x>7