What is the asymptotes of f(x)=(x^2-4x-5)/(x+1) ?

The asymptotes of f(x)=(x^2-4x-5)/(x+1) is Slant: y=x-5

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asymptotes of f(x)=(x^2-4x-5)/(x+1)

asymptotes

f (x) = \frac{x ^{2} - 4 x - 5}{x + 1}

Slant : y = x - 5

Solution steps

Vertical asymptotes of

\frac{x ^{2} - 4 x - 5}{x + 1} :

None

Horizontal Asymptotes of

\frac{x ^{2} - 4 x - 5}{x + 1} :

None

Slant Asymptotes of

\frac{x ^{2} - 4 x - 5}{x + 1} : y = x - 5

Slant : y = x - 5

f (x) = \frac{x ^{3}}{1 - x ^{2}}

4 x + y = 1

0.2 (y - 1)^{2} - 4

f (x) = \frac{1}{x}

\frac{2}{x + 2}

What is the asymptotes of f(x)=(x^2-4x-5)/(x+1) ?
The asymptotes of f(x)=(x^2-4x-5)/(x+1) is Slant: y=x-5