What is the inverse of-2x^2+3x-1 ?

The inverse of-2x^2+3x-1 is -(-3+sqrt(-8x+1))/4 ,-(-3-sqrt(-8x+1))/4

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inverse of-2x^2+3x-1

inverse

- 2 x^{2} + 3 x - 1

- \frac{- 3 + - 8 x + 1}{4}, - \frac{- 3 - - 8 x + 1}{4}

Solution steps

y = - 2 x^{2} + 3 x - 1

Replace

x

with

y

x = - 2 y^{2} + 3 y - 1

Solve for

y, x = - 2 y^{2} + 3 y - 1

- \frac{- 3 + - 8 x + 1}{4}, - \frac{- 3 - - 8 x + 1}{4}

(1, 3), (4, - 3)

(- 2, - 8), (4, 4)

\frac{- x}{3}

y - 1 = \frac{3}{5} (x + 5)

f (x) = x^{2} - 3

What is the inverse of-2x^2+3x-1 ?
The inverse of-2x^2+3x-1 is -(-3+sqrt(-8x+1))/4 ,-(-3-sqrt(-8x+1))/4