What is the inverse of f(x)=(6+\sqrt[3]{4x})/2 ?

The inverse of f(x)=(6+\sqrt[3]{4x})/2 is 2(x^3-9x^2+27x-27)

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inverse of f(x)=(6+\sqrt[3]{4x})/2

inverse

2 (x^{3} - 9 x^{2} + 27 x - 27)

Solution steps

Replace

x

with

y

Solve for

2 (x^{3} - 9 x^{2} + 27 x - 27)

lo g_{2} (x) - 2

f (x) = \frac{2 x}{x ^{2} + 1}

f (x) = - x^{2} + 8 x - 7

f (x) = \frac{3}{x - 2}

3 x^{4} - 4 x^{3} + 2

What is the inverse of f(x)=(6+\sqrt[3]{4x})/2 ?
The inverse of f(x)=(6+\sqrt[3]{4x})/2 is 2(x^3-9x^2+27x-27)