What is the domain of (x^2-9)/(x-3) ?

The domain of (x^2-9)/(x-3) is x 3

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domain of (x^2-9)/(x-3)

domain

\frac{x ^{2} - 9}{x - 3}

x < 3 or x > 3

Interval Notation

(- \infty, 3) \cup (3, \infty)

Solution steps

Find undefined (singularity) points:

x = 3

The function domain

x < 3 or x > 3

f (x) = \frac{x ^{2} + x - 2}{x + 1}

f (x) = x + \frac{81}{x}

2 + 4 + 11 x

f (x) = 10 x + 8

f (x) = ln (3) - ln (4 + x)

What is the domain of (x^2-9)/(x-3) ?
The domain of (x^2-9)/(x-3) is x<3\lor x>3