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Popular >

extreme F(x)=-9/(x^2+3)

Solution

extreme points

F (x) = - \frac{9}{x ^{2} + 3}

Solution

Minimum (0, - 3)

Solution steps

f^{'} (x) = \frac{18 x}{( x ^{2} + 3 ) ^{2}}

Find intervals:

Decreasing

: - \infty < x < 0,

Increasing

: 0 < x < \infty

Plug

x = 0

into

- \frac{9}{x ^{2} + 3} : - 3

Minimum (0, - 3)

Popular Examples

inflection f(x)=-x^7+7x^6 inflection points

f (x) = - x^{7} + 7 x^{6}

slope of y+2=-2(x-3)slope

y + 2 = - 2 (x - 3)

asymptotes of f(x)=(3x^2+1)/(x^2-2x-3)asymptotes

f (x) = \frac{3 x ^{2} + 1}{x ^{2} - 2 x - 3}

inverse of y=x^2-1,x<= 0 inverse

y = x^{2} - 1, x \leq 0

domain of f(x)=3+sqrt(16-x^2)domain

f (x) = 3 + 16 - x^{2}

Frequently Asked Questions (FAQ)

What is the extreme F(x)=-9/(x^2+3) ?
The extreme F(x)=-9/(x^2+3) is Minimum(0,-3)