What is the domain of y=(2x-1)/(x^2-x) ?

The domain of y=(2x-1)/(x^2-x) is x 1

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domain of y=(2x-1)/(x^2-x)

domain

y = \frac{2 x - 1}{x ^{2} - x}

x < 0 or 0 < x < 1 or x > 1

Interval Notation

(- \infty, 0) \cup (0, 1) \cup (1, \infty)

Solution steps

Find undefined (singularity) points:

x = 1, x = 0

The function domain

x < 0 or 0 < x < 1 or x > 1

f (x) = 0.8 x + \frac{72}{x}

f (x) = \frac{x ^{2} - x - 12}{x ^{2} + x - 6}

V (x) = x (24 - 4 x) (24 - 2 x)

f (x) = \frac{3}{x + 5}

x^{2} - 8 x + 2

What is the domain of y=(2x-1)/(x^2-x) ?
The domain of y=(2x-1)/(x^2-x) is x<0\lor 0<x<1\lor x>1