What is the domain of f(x)=sqrt(x^3+6x^2+8x) ?

The domain of f(x)=sqrt(x^3+6x^2+8x) is -4 = 0

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domain of f(x)=sqrt(x^3+6x^2+8x)

domain

f (x) = x^{3} + 6 x^{2} + 8 x

- 4 \leq x \leq - 2 or x \geq 0

Interval Notation

[- 4, - 2] \cup [0, \infty)

Solution steps

Find non-negative values for radicals:

- 4 \leq x \leq - 2 or x \geq 0

The function domain

- 4 \leq x \leq - 2 or x \geq 0

y^{2} - x - 25 = 0

f (x) = \frac{8}{x ^{2} + 3 x - 9}

f (x) = (x - 2)^{2} + 2

f (x) = 4 x^{5}

f (x) = \frac{8}{3} x + \frac{1}{2}

What is the domain of f(x)=sqrt(x^3+6x^2+8x) ?
The domain of f(x)=sqrt(x^3+6x^2+8x) is -4<= x<=-2\lor x>= 0