What is the critical x^3-3/2 x^2,-5<= x<= 4 ?

The critical x^3-3/2 x^2,-5<= x<= 4 is x=-5,x=0,x=1,x=4

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critical x^3-3/2 x^2,-5<= x<= 4

critical points

x^{3} - \frac{3}{2} x^{2}, - 5 \leq x \leq 4

x = - 5, x = 0, x = 1, x = 4

Solution steps

x^{3} - \frac{3}{2} x^{2}, - 5 \leq x \leq 4

Find where

f^{'} (x)

is equal to zero or undefined

x = 0, x = 1

Identify critical points not in

f (x)

domain

Domain of

x^{3} - \frac{3}{2} x^{2}, - 5 \leq x \leq 4 : - 5 \leq x \leq 4

All critical points are in domain

x = 0, x = 1

Evaluate interval endpoint

x = - 5 :

critical point

Evaluate interval endpoint

x = 4 :

critical point

x = - 5, x = 0, x = 1, x = 4

f (x) = \frac{x ^{2} + 1}{2 x ^{2} + 7}

4 (\frac{1}{2})^{x - 3} - 2

y = 5 x^{2}

- e^{x - 1} - 3

f (x) = \frac{1 - e ^{\frac{1}{x}}}{1 + e ^{\frac{1}{x}}}

What is the critical x^3-3/2 x^2,-5<= x<= 4 ?
The critical x^3-3/2 x^2,-5<= x<= 4 is x=-5,x=0,x=1,x=4