What is the domain of f(x)=sqrt((\sqrt{9-x^2))+2} ?

The domain of f(x)=sqrt((\sqrt{9-x^2))+2} is -3<= x<= 3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)=sqrt((\sqrt{9-x^2))+2}

domain

f (x) = (9 - x^{2}) + 2

- 3 \leq x \leq 3

Interval Notation

[- 3, 3]

Solution steps

Find non-negative values for radicals:

- 3 \leq x \leq 3

The function domain

- 3 \leq x \leq 3

f (x) = 1 + 7 + x

- 2 sin (6 x)

f (x) = 2 + x + 3

f (x) = 2 x^{3} + 13 x^{2} - 60 x - 3

\frac{x - 8}{x - 7}

What is the domain of f(x)=sqrt((\sqrt{9-x^2))+2} ?
The domain of f(x)=sqrt((\sqrt{9-x^2))+2} is -3<= x<= 3