What is the extreme f(x)=x^8e^x-3 ?

The extreme f(x)=x^8e^x-3 is Maximum(-8,(16777216)/(e^8)-3),Minimum(0,-3)

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extreme f(x)=x^8e^x-3

extreme points

f (x) = x^{8} e^{x} - 3

Maximum (- 8, \frac{16777216}{e ^{8}} - 3), Minimum (0, - 3)

Solution steps

f^{'} (x) = e^{x} x^{8} + 8 e^{x} x^{7}

Find intervals:

Increasing

: - \infty < x < - 8,

Decreasing

: - 8 < x < 0,

Increasing

: 0 < x < \infty

Plug

x = - 8

into

x^{8} e^{x} - 3 : \frac{16777216}{e ^{8}} - 3

Maximum (- 8, \frac{16777216}{e ^{8}} - 3)

Plug

x = 0

into

x^{8} e^{x} - 3 : - 3

Minimum (0, - 3)

Maximum (- 8, \frac{16777216}{e ^{8}} - 3), Minimum (0, - 3)

3 x - 2 y = 10

- x^{4} - 8 x^{3} - 15 x^{2}

- \frac{9}{( 2 + x ) ^{2}}

f (x) = \frac{x + 11}{x + 2} + \frac{1}{x}

\frac{2 - x}{x + 1}

What is the extreme f(x)=x^8e^x-3 ?
The extreme f(x)=x^8e^x-3 is Maximum(-8,(16777216)/(e^8)-3),Minimum(0,-3)