What is the inverse of f(x)=((x+1))/((x-1)) ?

The inverse of f(x)=((x+1))/((x-1)) is (1+x)/(x-1)

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inverse of f(x)=((x+1))/((x-1))

inverse

f (x) = \frac{( x + 1 )}{( x - 1 )}

\frac{1 + x}{x - 1}

Solution steps

y = \frac{x + 1}{x - 1}

Replace

x

with

y

x = \frac{y + 1}{y - 1}

Solve for

y, x = \frac{y + 1}{y - 1}

\frac{1 + x}{x - 1}

f (x) = 3 x^{2} - x^{3}

f (x) = \frac{x - 6}{x + 6}

(4.3) (1.2)

f (x) = 2 x - 3 y = 6

\frac{x ^{4}}{( 1 + x ) ^{3}}

What is the inverse of f(x)=((x+1))/((x-1)) ?
The inverse of f(x)=((x+1))/((x-1)) is (1+x)/(x-1)